Write the equation of the line in slope-intercept form that has the following points: (2, -1)(5, -3)

Answer:[tex]\large\boxed{y=-\dfrac{2}{3}x+\dfrac{1}{3}}[/tex]Step-by-step explanation:The skope-intercept form:[tex]y=mx+b[/tex]m - slopeb - y-interceptThe formula of a slope:[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]We have the points (2, -1) and (5, -3). Substitute:[tex]m=\dfrac{-3-(-1)}{5-2}=\dfrac{-3+1}{3}=\dfrac{-2}{3}=-\dfrac{2}{3}[/tex]We have the equation:[tex]y=-\dfrac{2}{3}x+b[/tex]Put the coordinates of the point (2 , -1) to the equation:[tex]-1=-\dfrac{2}{3}(2)+b[/tex][tex]-1=-\dfrac{4}{3}+b[/tex]           add 4/3 to both sides[tex]\dfrac{1}{3}=b\to b=\dfrac{1}{3}[/tex]Finally we have:[tex]y=-\dfrac{2}{3}x+\dfrac{1}{3}[/tex]